(x+3)*(3x^2+2x-4)=0

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Solution for (x+3)*(3x^2+2x-4)=0 equation: 


Simplifying
(x + 3)(3x2 + 2x + -4) = 0

Reorder the terms:
(3 + x)(3x2 + 2x + -4) = 0

Reorder the terms:
(3 + x)(-4 + 2x + 3x2) = 0

Multiply (3 + x) * (-4 + 2x + 3x2)
(3(-4 + 2x + 3x2) + x(-4 + 2x + 3x2)) = 0
((-4 * 3 + 2x * 3 + 3x2 * 3) + x(-4 + 2x + 3x2)) = 0
((-12 + 6x + 9x2) + x(-4 + 2x + 3x2)) = 0
(-12 + 6x + 9x2 + (-4 * x + 2x * x + 3x2 * x)) = 0
(-12 + 6x + 9x2 + (-4x + 2x2 + 3x3)) = 0

Reorder the terms:
(-12 + 6x + -4x + 9x2 + 2x2 + 3x3) = 0

Combine like terms: 6x + -4x = 2x
(-12 + 2x + 9x2 + 2x2 + 3x3) = 0

Combine like terms: 9x2 + 2x2 = 11x2
(-12 + 2x + 11x2 + 3x3) = 0

Solving
-12 + 2x + 11x2 + 3x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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